I’m taking high school AB Calculus.
I know the Evaluation Theorem states:
The definite integral from a to be of f(x) is the anti-derivative of b minus the anti-derivative of a. Doesn’t the Net Change Theorem say virtually the same thing?
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One Response
7.2.2009
As I think of it (First Year University Calculus Student here), it does say virtually the same thing.
The point really is that the Net Change Theorem defines the anti-derivative as a function in its own right, rather than an anti-derivative derived from another function.
Look here,
http://www.coolschool.ca/lor/CALC12/unit5/U05L04.htm